Quote:
Originally Posted by CRS
While I'm still being retarded..
A diluted bleach solution was found to have a concentration of 0.0222 M. It was originally prepared by diluting 3.0 mL of full-strength commercial bleach, with water, to a total volume of 100.00 mL. What is the molar concentration of NaOCl in the full-strength commercial bleach solution?
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I don't have much of a chem background but i did do chem 12.... twice...
0.0222mols/L =0.00222 mols/100mL
=0.00222mols/3.0mL because there were no mols in the 97ml of water added.
so... 0.00222mols/3.0ml x 1000ml/3ml = 0.74M?
But based on logic I think just calculate the molarity based off that?
I am probably wrong :/ oh wellz, google the question it seems pretty typical haha I feel really dumb now, but there I took a stab at it